The correct option is(A): 20.
Let point (a, a + 1) as the point of intersection of line and ellipse.
So,
\(\frac{a^2}{4}+\frac{a+1}{2}=1⇒a^2+2(a^2+2a+1)=4\)
\(⇒3a^2+4a-2=0\)
If the roots of this equation are α and β.
So, P(α, α + 1) and Q(β, β + 1)
PQ2 = 4r2 = (α – β)2 + (α – β)2
\(⇒9r^2=\frac{9}{4}(2(α-β)^2)\)
\(=\frac{9}{2}[(α+β)^2-4αβ]\)
\(=\frac{9}{2}[(-\frac{4}{3})^2+\frac{8}{3}]\)
\(=\frac{1}{2}[16+24]=20\)
The heat generated in 1 minute between points A and B in the given circuit, when a battery of 9 V with internal resistance of 1 \(\Omega\) is connected across these points is ______ J. 
The given circuit works as: 
Let the lines $L_1 : \vec r = \hat i + 2\hat j + 3\hat k + \lambda(2\hat i + 3\hat j + 4\hat k)$, $\lambda \in \mathbb{R}$ and $L_2 : \vec r = (4\hat i + \hat j) + \mu(5\hat i + + 2\hat j + \hat k)$, $\mu \in \mathbb{R}$ intersect at the point $R$. Let $P$ and $Q$ be the points lying on lines $L_1$ and $L_2$, respectively, such that $|PR|=\sqrt{29}$ and $|PQ|=\sqrt{\frac{47}{3}}$. If the point $P$ lies in the first octant, then $27(QR)^2$ is equal to}
A circle can be geometrically defined as a combination of all the points which lie at an equal distance from a fixed point called the centre. The concepts of the circle are very important in building a strong foundation in units likes mensuration and coordinate geometry. We use circle formulas in order to calculate the area, diameter, and circumference of a circle. The length between any point on the circle and its centre is its radius.
Any line that passes through the centre of the circle and connects two points of the circle is the diameter of the circle. The radius is half the length of the diameter of the circle. The area of the circle describes the amount of space that is covered by the circle and the circumference is the length of the boundary of the circle.
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