The Lewis acid character of boron tri halides follows the order :
Extent of back bonding reduces down the group leading to more Lewis acidic strength.
For example, \( \text{BF}_3 \) has the most extent of back bonding due to the \( 2p - 2p \) interaction, whereas \( \text{BCl}_3 \) and \( \text{BBr}_3 \) show less back bonding.
Therefore, the Lewis acid strength increases from \( \text{BF}_3 \) to \( \text{BCl}_3 \), \( \text{BBr}_3 \), and finally \( \text{B}_1 \).
Thus, the correct order is \( \text{B}_1 > \text{BBr}_3 > \text{BCl}_3 > \text{BF}_3 \).
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :
