Question:

The IUPAC name of the following compound is :

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Pick the longest chain that contains the double bond and number it so the double bond gets the lowest locant.
Updated On: Nov 11, 2026
  • 4-methyl-3-ethylhex-4-ene
  • 3-ethyl-4-methylhex-4-ene
  • 4-ethyl-3-methylhex-2-ene
  • 4, 4- diethyl-3-methylbut-2-ene
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The Correct Option is C

Solution and Explanation

The skeleton is \(\mathrm{CH_3CH_2-CH(C_2H_5)-C(CH_3)=CH-CH_3}\).
The longest chain containing the C=C has 6 carbons (hexene).
Number from the end nearer the double bond: \(\mathrm{CH_3(1)-CH(2)=C(3)(CH_3)-CH(4)(C_2H_5)-CH_2(5)-CH_3(6)}\); the double bond is at C2 (numbering from the other end would give C4).
Substituents: methyl on C3, ethyl on C4, cited alphabetically: 4-ethyl-3-methylhex-2-ene.
Answer: (3) 4-ethyl-3-methylhex-2-ene
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