Question:

The IUPAC name for the following compound is :

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Choose the longest chain that contains both the double and triple bond; give the lowest locants to multiple bonds, and in a tie give the double bond the lower number.
Updated On: Nov 11, 2026
  • 3, 5-dimethyl-4-propylhept-1-en-6-yne
  • 3-methyl-4-(3-methylprop-1-enyl)-1-heptyne
  • 3-methyl-4-(1-methylprop-2-enyl)-1-heptene
  • 3,5-dimethyl-4-propylhept-6-en-1-yne
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The Correct Option is A

Solution and Explanation

The structure is \(\mathrm{HC{\equiv}C{-}CH(CH_3){-}CH(CH_2CH_2CH_3){-}CH(CH_3){-}CH{=}CH_2}\).
The principal chain must include both the C=C and the \(\mathrm{C{\equiv}C}\): it has 7 carbons (hept), with a propyl group on the middle carbon and two methyl groups.
Numbering from either end gives the multiple-bond locants {1,6}; the tie is broken by giving the double bond the lower locant, so C=C is C1 and the triple bond is C6-C7.
Then the methyls are at C3 and C5, and propyl at C4.
Name: 3,5-dimethyl-4-propylhept-1-en-6-yne.
Answer: (1) 3, 5-dimethyl-4-propylhept-1-en-6-yne
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