Question:

The IUPAC name for the following compound is

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A carboxylic acid has higher priority than an aldehyde, so the chain is numbered from the \(\mathrm{COOH}\) carbon and the CHO is named as an oxo group.
Updated On: Nov 5, 2026
  • 2, 5-dimethyl-6-carboxy-hex-3-enal
  • 6-formyl-2-methyl-hex-3-enoic acid
  • 2, 5-dimethyl-5-carboxy-hex-3-enal
  • 2, 5-dimethyl-6-oxo-hex-3-enoic acid
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The Correct Option is D

Solution and Explanation

The compound is \(\mathrm{OHC-CH(CH_3)-CH=CH-CH(CH_3)-COOH}\).
Principal functional group: \(\mathrm{-COOH}\) (acid outranks aldehyde), so the name ends in -oic acid and the CHO is expressed as the prefix oxo.
Longest chain containing the principal group: C1 = COOH, C2 = \(\mathrm{CH(CH_3)}\), C3=C4 double bond, C5 = \(\mathrm{CH(CH_3)}\), C6 = CHO carbon (6-oxo).
Substituents: methyl at C2 and C5, oxo at C6, double bond at C3.
Name: 2,5-dimethyl-6-oxohex-3-enoic acid.
Answer: (4) 2, 5-dimethyl-6-oxo-hex-3-enoic acid
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