Question:

The internuclear distances in O \(-\) O bonds for \(\mathrm{O_2^+, O_2, O_2^-}\) and \(\mathrm{O_2^{2-}}\) respectively are :

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Bond length is inversely related to bond order; compute the bond order of each species by MOT.
Updated On: Nov 4, 2026
  • 1.30 \(\mathrm{\AA}\), 1.49 \(\mathrm{\AA}\), 1.12 \(\mathrm{\AA}\), 1.21 \(\mathrm{\AA}\)
  • 1.49 \(\mathrm{\AA}\), 1.21 \(\mathrm{\AA}\), 1.12 \(\mathrm{\AA}\), 1.30 \(\mathrm{\AA}\)
  • 1.21 \(\mathrm{\AA}\), 1.12 \(\mathrm{\AA}\), 1.49 \(\mathrm{\AA}\), 1.30 \(\mathrm{\AA}\)
  • 1.12 \(\mathrm{\AA}\), 1.21 \(\mathrm{\AA}\), 1.30 \(\mathrm{\AA}\), 1.49 \(\mathrm{\AA}\)
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The Correct Option is D

Solution and Explanation

Bond orders from molecular orbital theory: \(\mathrm{O_2^+}\) = 2.5, \(\mathrm{O_2}\) = 2, \(\mathrm{O_2^-}\) = 1.5, \(\mathrm{O_2^{2-}}\) = 1.
Bond length decreases as bond order increases, so the order of length is \(\mathrm{O_2^+} \lt \mathrm{O_2} \lt \mathrm{O_2^-} \lt \mathrm{O_2^{2-}}\).
Known values: 1.12, 1.21, 1.30, 1.49 \(\mathrm{\AA}\) in that order.
Answer: (4) 1.12 \(\mathrm{\AA}\), 1.21 \(\mathrm{\AA}\), 1.30 \(\mathrm{\AA}\), 1.49 \(\mathrm{\AA}\)
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