Step 1: Calculate volume using the ratio of dimensions.
Let the length, width, and height of the box be \( 5k, 3k, \) and \( 2k \) respectively, where \( k \) is a constant.
The volume \( V \) of the box is given by:
\[
V = \text{length} \times \text{width} \times \text{height} = 5k \times 3k \times 2k = 30k^3
\]
We are told that the volume is \( m \), so:
\[
30k^3 = m \quad \Rightarrow \quad k^3 = \frac{m}{30} \quad \Rightarrow \quad k = \sqrt[3]{\frac{m}{30}}
\]
Step 2: Calculate the length.
The length is \( 5k \), so:
\[
\text{Length} = 5 \times \sqrt[3]{\frac{m}{30}} = \sqrt{\frac{25m}{6}}
\]
Step 3: Conclusion.
The correct answer is (A).