The increasing order of the boiling points of the major products A, B and C of the following reactions will be :
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- A < C < B
- C < A < B
- B < C < A
- A < B < C
The Correct Option is C
Solution and Explanation
(b) 2-Methylpropene + HBr gives the Markovnikov product B = tert-butyl bromide (\((\mathrm{CH_3})_3\mathrm{CBr}\)), b.p. about 346 K.
(c) 2-Butene + HBr gives C = 2-bromobutane (\(\mathrm{CH_3CHBrCH_2CH_3}\)), b.p. about 364 K.
Among isomeric alkyl halides, boiling point decreases with branching (smaller surface area, weaker van der Waals forces): primary > secondary > tertiary.
So B < C < A.
Answer: (3) B < C < A
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