Question:

The incorrect statement is :

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Count the d-electrons: manganate has Mn(VI), permanganate has Mn(VII).
Updated On: Nov 5, 2026
  • In manganate and permanganate ions, the \(\pi\)-bonding takes place by overlap of p-orbitals of oxygen and d-orbitals of manganese
  • Manganate ion is green in colour and permanganate ion in purple in colour
  • Manganate and permanganate ions are paramagnetic
  • Manganate and permanganate ions are tetrahedral
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The Correct Option is C

Solution and Explanation

Manganate ion: \(\mathrm{MnO_4^{2-}}\), Mn is in +6 state, configuration \(3d^1\) (one unpaired electron), so it is paramagnetic and green.
Permanganate ion: \(\mathrm{MnO_4^-}\), Mn is in +7 state, configuration \(3d^0\) (no unpaired electron), so it is diamagnetic and purple.
Both ions are tetrahedral (\(sp^3\) / \(d^3s\)) and the \(\pi\)-bonds are formed by \(p\pi\)-\(d\pi\) overlap of oxygen p-orbitals with manganese d-orbitals, so statements (1), (2) and (4) are correct.
Statement (3) is wrong because permanganate is diamagnetic.
Answer: (3) Manganate and permanganate ions are paramagnetic
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