Question:
The hydrolysis products of \(\mathrm{ICl}\), \(\mathrm{ClF_3}\), and \(\mathrm{BrF_5}\) are respectively:
The hydrolysis products of \(\mathrm{ICl}\), \(\mathrm{ClF_3}\), and \(\mathrm{BrF_5}\) are respectively:
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Interhalogen compounds on hydrolysis often yield oxyacids of the more electronegative halogen. Recognize oxidation states for correct products.
Updated On: May 18, 2025
- HIO, HClO\(_3\), and HBrO\(_3\)
- HIO, HClO\(_2\), and HBrO\(_3\)
- HCl, HF, and HBrO\(_3\)
- HClO, HClO\(_3\), and HBrO\(_3\)
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The Correct Option is A
Solution and Explanation
Let us consider the hydrolysis reactions of the given interhalogen compounds:
1. ICl (Iodine monochloride):
On hydrolysis:
\[
\mathrm{ICl + H_2O \rightarrow HIO + HCl}
\]
Thus, it forms hypoiodous acid (HIO) — a weak monobasic acid.
2. ClF\(_3\) (Chlorine trifluoride):
On hydrolysis:
\[
\mathrm{ClF_3 + 3H_2O \rightarrow HClO_3 + 3HF}
\]
Here, \(\mathrm{HClO_3}\) is chloric acid (oxidation state of Cl = +5).
3. BrF\(_5\) (Bromine pentafluoride):
On hydrolysis:
\[
\mathrm{BrF_5 + 3H_2O \rightarrow HBrO_3 + 5HF}
\]
Here, \(\mathrm{HBrO_3}\) is bromic acid (oxidation state of Br = +5).
Therefore, the correct set of hydrolysis products is:
HIO, HClO\(_3\), and HBrO\(_3\)
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