Question:

The hydrocarbon with seven carbon atoms containing a neopentyl and a vinyl group is :

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Neopentyl is \(\mathrm{-CH_2C(CH_3)_3}\) (5 C) and vinyl is \(\mathrm{-CH=CH_2}\) (2 C); join them and match the name.
Updated On: Nov 11, 2026
  • 2, 2-dimethyl-4-pentene
  • Isopropyl-2-butene
  • 4, 4-dimethylpentene
  • 2, 2-dimethyl-3-pentene
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The Correct Option is A

Solution and Explanation

Neopentyl group = \(\mathrm{-CH_2-C(CH_3)_3}\) (5 carbons); vinyl group = \(\mathrm{-CH=CH_2}\) (2 carbons). Total 7 carbons.
Joining them gives \(\mathrm{CH_2=CH-CH_2-C(CH_3)_3}\).
The chain \(\mathrm{CH_2=CH-CH_2-C(CH_3)_2-CH_3}\) has 5 carbons with two methyl groups on the carbon next to the chain end; numbered from the double-bond end it is 4,4-dimethyl-1-pentene, and the option names the same compound as 2,2-dimethyl-4-pentene (numbered from the other end).
Option (2) has an isopropyl group, and option (4) puts a tert-butyl group directly on the double bond (no neopentyl or vinyl). Option (3) is an incomplete name (no double bond locant). So option (1) is the intended answer.
Answer: (1) 2, 2-dimethyl-4-pentene
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