The hydride that is NOT electron deficient :
Show Hint
- \(\mathrm{B_2H_6}\)
- \(\mathrm{AlH_3}\)
- \(\mathrm{GaH_3}\)
- \(\mathrm{SiH_4}\)
The Correct Option is D
Solution and Explanation
Group 13 elements (B, Al, Ga) have 3 valence electrons. In \(\mathrm{BH_3}\)/\(\mathrm{B_2H_6}\), \(\mathrm{AlH_3}\) and \(\mathrm{GaH_3}\) the central atom forms only 3 bonds, so it has 6 electrons and is electron deficient (\(\mathrm{B_2H_6}\) is stabilised by 3-centre-2-electron bridging bonds).
Silicon (Group 14) has 4 valence electrons and forms 4 bonds in \(\mathrm{SiH_4}\), giving a complete octet. So \(\mathrm{SiH_4}\) is electron precise, not electron deficient.
Answer: (4) \(\mathrm{SiH_4}\)
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