Question

The hole and the shaft dimensions (in mm) are given as
Hole dimension = \(30 \pm 0.04\)  and  Shaft dimension = \(30 \pm 0.06\). 
The maximum possible clearance (in mm) is .......... (Rounded off to two decimal places)
 

Hint:

When calculating the clearance, always use the maximum hole size and the minimum shaft size to get the largest possible clearance.

Answer 1

The clearance between the hole and the shaft is given by the difference between the hole's maximum dimension and the shaft's minimum dimension. 
Given: 
- The hole dimension is \(30 \pm 0.04\), which means the maximum hole size is \(30 + 0.04 = 30.04 \, {mm}\), 
- The shaft dimension is \(30 \pm 0.06\), which means the minimum shaft size is \(30 - 0.06 = 29.94 \, {mm}\). 
The maximum possible clearance is the difference between the maximum hole size and the minimum shaft size: 
\[ {Clearance} = 30.04 - 29.94 = 0.10 \, {mm} \] Thus, the maximum possible clearance is 0.01 mm.