Question:

The highest value of the calculated spin only magnetic moment (in BM) among all the transition metal complexes is :

Show Hint

Use \(\mu=\sqrt{n(n+2)}\) BM; the d-subshell holds at most 5 unpaired electrons.
Updated On: Nov 5, 2026
  • 5.92
  • 6.93
  • 3.87
  • 4.90
Show Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Spin-only moment \(\mu=\sqrt{n(n+2)}\) BM, where n = number of unpaired electrons.
A transition metal ion has only five d-orbitals, so the maximum number of unpaired electrons is 5 (high-spin \(d^5\), e.g. \(\mathrm{Mn^{2+}}\), \(\mathrm{Fe^{3+}}\)).
\(\mu_{max}=\sqrt{5\times7}=\sqrt{35}=5.92\) BM.
Check others: n = 6 would give \(\sqrt{48}=6.93\) BM (impossible for d-block), n = 3 gives 3.87, n = 4 gives 4.90.
Answer: (1) 5.92
Was this answer helpful?
0
0