We know the relationship between H.C.F., L.C.M., and the product of two numbers:
\[
\text{H.C.F.} \times \text{L.C.M.} = \text{Number 1} \times \text{Number 2}.
\]
Let the numbers be \( x \) and \( 5 \). We are given:
\[
\text{H.C.F.} = 15, \quad \text{L.C.M.} = 105.
\]
Substituting the known values:
\[
15 \times 105 = 5 \times x.
\]
Solving for \( x \):
\[
1575 = 5x \quad \Rightarrow \quad x = \frac{1575}{5} = 315.
\]
Thus, the other number is \( \boxed{75} \).