The group having isoelectronic species is:
Show Hint
- \(\mathrm{O^{2-},\ F^-,\ Na^+,\ Mg^{2+}}\)
- \(\mathrm{O^{2-},\ F^-,\ Na,\ Mg^{2+}}\)
- \(\mathrm{O^-,\ F^-,\ Na^+,\ Mg^{2+}}\)
- \(\mathrm{O^-,\ F^-,\ Na,\ Mg^+}\)
The Correct Option is A
Solution and Explanation
\(\mathrm{O^{2-}}\): 10 e, \(\mathrm{F^-}\): 10 e, \(\mathrm{Na^+}\): 10 e, \(\mathrm{Mg^{2+}}\): 10 e. All have 10 electrons (Ne configuration).
Option (2) contains neutral Na (11 e); option (3) contains \(\mathrm{O^-}\) (9 e); option (4) contains \(\mathrm{O^-}\) (9 e), Na (11 e) and \(\mathrm{Mg^+}\) (11 e).
Answer: (1) \(\mathrm{O^{2-},\ F^-,\ Na^+,\ Mg^{2+}}\)
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