Concept:
This problem is based on the multiplication principle of counting.
If an event can occur in \(m\) ways and another independent event can occur in \(n\) ways, then the total number of ways both events can occur together is \(m \times n\).
Step 1: Identify choices at each entrance
Number of entrances \(=3\)
For each entrance, a person can use:
Stairs, or
Elevator
So, number of choices per entrance \(=2\).
Step 2: Apply multiplication principle
\[
\text{Total ways} = 3 \times 2 = 6
\]
Conclusion:
A person can enter the building in \(\boxed{6}\) different ways.
Final Answer: \(\boxed{6}\)