Question

The following graphs show the total quantity (in kg) of five different fruits sold by two fruit sellers A and B. Graph 1 shows the total quantity (in kg) of fruits sold, and Graph 2 shows the selling price per kg of fruits sold by the sellers. If 20% of the apples bought by fruit seller A were rotten and 10% of the apples bought by fruit seller B were rotten, and they sold all the remaining apples, what is the ratio of the quantities of apples bought by fruit sellers A and B?

• A. 6:5
• B. 5:4
• C. 4:3
• D. 3:2
• E. 2:3

Hint:

When dealing with percentages of rotten or damaged goods, calculate the effective quantity sold (100% minus the rotten percentage) and then divide the sold quantity by the remaining percentage to find the total quantity bought.

Answer 1

The Correct Option is D

Step 1: Given Data
From the first graph, the total quantity of apples sold by seller A and seller B is: - Seller A: 120 kg of apples - Seller B: 90 kg of apples Step 2: Calculate the total apples bought by each seller
- For Seller A: Since 20% of the apples bought by seller A were rotten, 80% of the apples were sold. Therefore, the total quantity of apples bought by seller A is: \[ \text{Total apples bought by A} = \frac{120}{0.80} = 150 \, \text{kg} \] - For Seller B: Since 10% of the apples bought by seller B were rotten, 90% of the apples were sold. Therefore, the total quantity of apples bought by seller B is: \[ \text{Total apples bought by B} = \frac{90}{0.90} = 100 \, \text{kg} \] Step 3: Find the ratio of apples bought by seller A and seller B
The ratio of apples bought by seller A to seller B is: \[ \text{Ratio of apples bought by A and B} = \frac{150}{100} = 3:2 \] Step 4: Conclusion
Thus, the ratio of the quantities of apples bought by fruit sellers A and B is 3:2. Therefore, the correct answer is (D).