Question:
The following graph is obtained for the adsorption of a gas on the surface of a catalyst. The values of k and n are respectively
The following graph is obtained for the adsorption of a gas on the surface of a catalyst. The values of k and n are respectively
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For adsorption isotherms, the slope and intercept of the graph provide key information regarding the rate of adsorption and the constants involved.
Updated On: Mar 6, 2026
- \(2, \frac{1}{m}\)
- \(1, 2\)
- \(100, 1\)
\(m, 100\)
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The Correct Option is C
Solution and Explanation
The given graph is of the form \( x = \log p \) and \( y = \log \left( \frac{x}{m} \right) \). The slope of the graph is represented by \( m \), and it is related to the adsorption isotherm.
The equation that follows from the graph is of the form:
\[
k = \text{slope} \times \left( \frac{x}{m} \right)
\]
Here, from the graph, the slope is \( 100 \), so the value of \( n \) is 1. Therefore, the values of \( k \) and \( n \) are \( 100 \) and \( 1 \) respectively.
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