To arrange the given carboxylic acids in decreasing order of their pKa values, we need to understand the relationship between the structure of carboxylic acids and their acidity.
The pKa value is a measure of the strength of an acid. The lower the pKa, the stronger the acid. This is because a strong acid dissociates more completely in solution, releasing more protons (H+ ions).
In carboxylic acids, the presence of electron-withdrawing groups increases acidity (thus lowering the pKa) by stabilizing the negative charge on the conjugate base (carboxylate ion) through resonance or induction. Conversely, electron-donating groups decrease acidity (thus increasing the pKa).
Thus, the order of decreasing pKa values (i.e., increasing acidity) is as follows:
Hence, the correct order is indeed ii > i > iv > iii.
| Group I | Group II |
| P) NaCl | 1) Coordination bond |
| Q) $H_2$ | 2) Polar covalent bond |
| R) $Pd-P$ bond in $Pd(PPh_3)_4 | 3) Covalent bond |
| S) $C-Cl$ bond in $CH_3Cl $ | 4) Ionic bond |

