The fluid flow through an under-saturated oil reservoir is driven by solution gas drive mechanism. The reservoir parameters are as given below.
\(\text{Compressibility of water, } c_w = 1 \times 10^{-6} \, \text{psi}^{-1}, \\ \text{Compressibility of formation, } c_f = 1 \times 10^{-5} \, \text{psi}^{-1},\)
\( \text{Connate water saturation, } S_{wc} = 0.2, \\ \text{Initial reservoir pressure, } p_i = 4000 \, \text{psi}, \\ \text{Reservoir pressure at bubble-point, } p_b = 3000 \, \text{psi},\)
\( \text{Oil formation volume factor, } B_{oi} = 1.24 \, \text{rb/STB}, \\ \text{Formation volume factor at bubble point pressure, } B_{ob} = 1.26 \, \text{rb/STB.}\)
The percentage of oil recovered as a fraction of the Original Oil in Place (OOIP) is \(\underline{\hspace{2cm}}\)% (round off to one decimal place).
The fluid flow through an under-saturated oil reservoir is driven by solution gas drive mechanism. The reservoir parameters are as given below.
\(\text{Compressibility of water, } c_w = 1 \times 10^{-6} \, \text{psi}^{-1}, \\ \text{Compressibility of formation, } c_f = 1 \times 10^{-5} \, \text{psi}^{-1},\)
\( \text{Connate water saturation, } S_{wc} = 0.2, \\ \text{Initial reservoir pressure, } p_i = 4000 \, \text{psi}, \\ \text{Reservoir pressure at bubble-point, } p_b = 3000 \, \text{psi},\)
\( \text{Oil formation volume factor, } B_{oi} = 1.24 \, \text{rb/STB}, \\ \text{Formation volume factor at bubble point pressure, } B_{ob} = 1.26 \, \text{rb/STB.}\)
The percentage of oil recovered as a fraction of the Original Oil in Place (OOIP) is \(\underline{\hspace{2cm}}\)% (round off to one decimal place).
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Correct Answer: 2.6
Solution and Explanation
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