The first ionisation potential of $Na$ is $5.1\, eV$. The value of electron gain enthalpy of $Na^+$ will be
- $- 2.55\, eV$
- $- 5.1\, eV$
- $- 10.2\, eV$
- $+ 2.55\, eV$
The Correct Option is B
Solution and Explanation
$Na^+ + e^- \longrightarrow Na$
Electron gain enthalpy of Na+ is reverse of (IE) Because reaction is reverse so
$ \, \, \, \, \, ? H (eq) = - 5.1 \, eV$
Top Questions on Classification
- What is classification? Point out its utility. Explain.
- UP Board XII - 2023
- Tark Shastra
- Classification
- Write notes on the following:
(i) Fallacy of classification.
(ii) Classification and definition.- UP Board XII - 2023
- Tark Shastra
- Classification
Which letter is midway between the 13th letter from the left and the 4th letter from the right in the sequence given below?
USBEYFHKOPRAWCGJMQDIVLNTXZ- Karnataka PGCET - 2023
- Logical Reasoning
- Classification
- Find the odd one out: Symphony, Orchestra, Guitar, Mob
- CLAT - 2019
- Logical Reasoning
- Classification
- Find the odd-man out:
- CLAT - 2019
- Logical Reasoning
- Classification
Questions Asked in JEE Main exam
- The final product [B] is:
- JEE Main - 2026
- Organic Chemistry
- Let $f(\alpha)$ denote the area of the region in the first quadrant bounded by $x=0$, $x=1$, $y^2=x$ and $y=|\alpha x-5|-|1-\alpha x|+\alpha^2$. Then $(f(0)+f(1))$ is equal to
- JEE Main - 2026
- Calculus
If a random variable \( x \) has the probability distribution
then \( P(3<x \leq 6) \) is equal to- JEE Main - 2026
- Conditional Probability
- Two distinct numbers $a$ and $b$ are selected at random from $1, 2, 3, \ldots, 50$. The probability that their product $ab$ is divisible by $3$ is
- JEE Main - 2026
- Probability
- Consider a modified Bernoulli equation. \[ P + \frac{A}{Bt^2} + \rho g(h + Bt) + \frac{1}{2} \rho v^2 = \text{constant} \] If t has the dimension of time then the dimensions of A and B are_________ respectively.
- JEE Main - 2026
- Units, Dimensions and Measurements
Concepts Used:
Haloalkanes and Haloarenes - Classification
Classification of Haloalkanes and Haloarenes are as follows:
Haloalkanes and Haloarenes are Classified on the Basis of the Number of Halogen Atoms:
These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;
- Monohaloalkane
- Dihaloalkane
- Trihaloalkane
Haloalkanes and Haloarenes are Classified on Compounds Containing sp3 C—X Bond (X= F, Cl, Br, I)
This class includes:
- Alkyl halides or haloalkanes (R—X)
- Allylic halides
- Benzylic halides
Haloalkanes and Haloarenes are Classified on Compounds Containing sp2 C—X Bond
This class includes:
- Vinylic halides
- Aryl halides