Question:

The equation of the straight line passing through the point (−1, 2) and perpendicular to the line $x + 3y = 4$ is:

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A line perpendicular to $Ax + By = C$ is of the form $Bx - Ay = k$.
Updated On: Jun 26, 2026
  • $x - y - 3 = 0$
  • $3x + y + 1 = 0$
  • $3x - y + 5 = 0$
  • $3x - y + 10 = 0$
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Slopes of perpendicular lines.

Step 2: Analysis

The slope of $x + 3y = 4$ is $m_1 = -1/3$. The slope of a perpendicular line is $m_2 = -1/m_1 = 3$.

Step 3: Calculation

Using point-slope form: $y - 2 = 3(x - (-1))$.
$y - 2 = 3x + 3 \implies 3x - y + 5 = 0$.

Step 4: Conclusion

The equation of the line is $3x - y + 5 = 0$. Final Answer: (C)
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