Question:
The element with atomic number 114 has outer shell electron configuration as that of element 'X'. What is X?
The element with atomic number 114 has outer shell electron configuration as that of element 'X'. What is X?
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Elements of the same group have identical valence shell configurations. Identify the group first, then match the option from that group.
Updated On: Jun 15, 2026
- $\text{Ar}$
- $\text{Ge}$
- $\text{Se}$
- $\text{Ti}$
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The Correct Option is B
Solution and Explanation
Concept:
Elements belonging to the same group possess the same outer electronic configuration.
Element with atomic number $114$ is Flerovium (Fl).
Step 1: Determine the group of element 114 Flerovium belongs to Group 14 of the periodic table. The general valence shell configuration of Group 14 elements is \[ ns^2np^2 \]
Step 2: Identify the corresponding element Group 14 elements are \[ \text{C},\ \text{Si},\ \text{Ge},\ \text{Sn},\ \text{Pb},\ \text{Fl} \] Among the given options, only Germanium belongs to Group 14. Its outer electronic configuration is \[ 4s^24p^2 \] which is analogous to \[ 7s^27p^2 \] for Flerovium. Therefore, \[ \boxed{\text{Ge}} \]
Step 1: Determine the group of element 114 Flerovium belongs to Group 14 of the periodic table. The general valence shell configuration of Group 14 elements is \[ ns^2np^2 \]
Step 2: Identify the corresponding element Group 14 elements are \[ \text{C},\ \text{Si},\ \text{Ge},\ \text{Sn},\ \text{Pb},\ \text{Fl} \] Among the given options, only Germanium belongs to Group 14. Its outer electronic configuration is \[ 4s^24p^2 \] which is analogous to \[ 7s^27p^2 \] for Flerovium. Therefore, \[ \boxed{\text{Ge}} \]
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