To solve for the non-dimensional parameters, we need to apply Buckingham’s Pi Theorem, which helps derive dimensionless parameters (Pi terms). Starting with the drag force equation: \[ F_D = F(D, V, \rho, \mu) \] We express the dimensions: \[ F_D = [M L T^{-2}], \quad \rho = [M L^{-3}], \quad V = [L T^{-1}], \quad \mu = [M L^{-1} T^{-1}] \] We substitute these into the drag force equation and apply the Buckingham’s Pi Theorem. After calculating, the resulting non-dimensional parameters are: \[ \pi_1 = \frac{F_D}{\rho V^2 D^2}, \quad \pi_2 = \frac{\rho V D}{\mu} \] Both expressions are dimensionless and represent the non-dimensional parameters related to the drag force on the sphere.
Hence, the correct answers are (A) and (C).

A flexible chain of mass $m$ is hanging as shown. Find tension at the lowest point. 