The distance of the point \(P(-6, 8)\) from the origin is:
Show Hint
To calculate the distance of a point from the origin, use the distance formula \(d = \sqrt{x^2 + y^2}\), where \(x\) and \(y\) are the coordinates of the point.
The distance of a point \(P(x, y)\) from the origin \((0, 0)\) is given by the distance formula:
\[
d = \sqrt{x^2 + y^2}
\]
Here, the coordinates of the point \(P\) are \((-6, 8)\).
Substitute \(x = -6\) and \(y = 8\) into the distance formula:
\[
d = \sqrt{(-6)^2 + 8^2} = \sqrt{36 + 64} = \sqrt{100} = 10
\]
Step 2: Conclusion.
Therefore, the distance of the point \(P(-6, 8)\) from the origin is 10 units.
Final Answer:} 10.