Question:
The distance between the two planes 2x + 3y + 4z = 4 and 4x + 6y +8z = 12 is
The distance between the two planes 2x + 3y + 4z = 4 and 4x + 6y +8z = 12 is
Updated On: Apr 26, 2024
- 2 units
- 8 units
- \(\frac{2}{\sqrt {29}}\) units
- 4 units
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The Correct Option is C
Solution and Explanation
The correct answer is Option (C) : \(\frac{2}{\sqrt {29}}\) units
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