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the distance between the points 2 cos theta 0 and
Question:
The distance between the points \( (2\cos\theta, 0) \) and \( (0, 2\sin\theta) \) is:
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The Pythagorean identity \( \cos^2\theta + \sin^2\theta = 1 \) simplifies many distance calculations.
Bihar Board X - 2024
Bihar Board X
Updated On:
Oct 27, 2025
\( 1 \)
\( 2 \)
\( 3 \)
\( 4 \)
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The Correct Option is
D
Solution and Explanation
Step 1: Use the distance formula
The distance between two points \( (x_1, y_1) \) and \( (x_2, y_2) \) is given by: \[ d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \]
Step 2: Substitute values
Given points: - \( (2\cos\theta, 0) \) - \( (0, 2\sin\theta) \) \[ d = \sqrt{(0 - 2\cos\theta)^2 + (2\sin\theta - 0)^2} \] \[ = \sqrt{(2\cos\theta)^2 + (2\sin\theta)^2} \] \[ = \sqrt{4\cos^2\theta + 4\sin^2\theta} \] \[ = \sqrt{4(\cos^2\theta + \sin^2\theta)} \] \[ = \sqrt{4(1)} \] \[ = \sqrt{4} = 2 \] Thus, the correct answer is \( 2 \).
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