Instead of jumping straight to the parallel-line distance formula, the same answer can be reached by picking a specific point on one line and measuring its perpendicular distance to the other, since the two lines never converge, that distance is the same everywhere along them.
\[ \text{Set } y = 0 \text{ in } 3x + 4y + 5 = 0 \implies 3x + 5 = 0 \implies x = -\frac{5}{3} \]So \(\left(-\dfrac{5}{3}, 0\right)\) is a point on the first line. Its perpendicular distance to the second line \(3x + 4y - 7 = 0\) is:
\[ d = \frac{\left|3\left(-\frac{5}{3}\right) + 4(0) - 7\right|}{\sqrt{3^2+4^2}} = \frac{|-5-7|}{5} = \frac{12}{5} \]Comparing this to each option below:
The direct geometric check, placing a real point on one line and measuring how far it sits from the other, confirms the same separation.
Therefore, the correct answer is 12/5.