Question

The discriminant of the quadratic equation \(x^{2}+4x+b=0\) is

• A. \(16-4b\)
• B. \(4b-16\)
• C. \(b^{2}-16\)
• D. \(16-b^{2}\)

Hint:

For quadratic equations in the form \(x^{2}+px+q=0\), the discriminant is \(p^{2}-4q\).

Answer 1

The Correct Option is A

Step 1: Recall the discriminant formula.
For \(ax^{2}+bx+c=0\), the discriminant is \(D=b^{2}-4ac\).
Step 2: Identify coefficients.
Here \(a=1,\ b=4,\ c=b\).
Step 3: Substitute values.
\[ D = 4^{2} - 4(1)(b) = 16 - 4b \]