Step 1: Differentiate the given equation \( bx + ay = ab \) with respect to \( x \).
\[ b + a\frac{dy}{dx} = 0 \]
Step 2: This first derivative shows that \( \frac{dy}{dx} = -\frac{b}{a} \), which is a constant value since \(a\) and \(b\) are constants.
Step 3: Differentiate the result from Step 1 again with respect to \( x \). The derivative of a constant (\(b\)) is zero, and the derivative of a constant times a function (\(a\frac{dy}{dx}\)) is the constant times the derivative of the function.
\[ 0 + a\frac{d^2y}{dx^2} = 0 \implies \frac{d^2y}{dx^2} = 0 \]
The statement is true.