The difference between electron gain enthalpies will be maximum between
- Ne and F
- Ne and Cl
- Ar and Cl
- Ar and F
The Correct Option is B
Solution and Explanation
Solution: Difference in Electron Gain Enthalpy
Electron gain enthalpy refers to the energy change that occurs when an electron is added to an isolated gaseous atom to form a gaseous ion.
Explanation:
- Neon (Ne): Neon is a noble gas with a completely filled electronic configuration (1s2 2s2 2p6).
- It has a stable structure, and adding an electron would require placing it in the higher energy 3s orbital.
- As a result, the electron gain enthalpy of Neon is highly positive because energy is absorbed rather than released.
- Chlorine (Cl): Chlorine is a halogen with the electronic configuration (1s2 2s2 2p6 3s2 3p5).
- It has a high tendency to gain an electron to achieve a stable noble gas configuration (3p6).
- The electron gain enthalpy of chlorine is highly negative, as energy is released when it gains an electron.
Conclusion: The difference in electron gain enthalpy between Neon and Chlorine is maximum because:
- Neon has a highly positive electron gain enthalpy.
- Chlorine has a highly negative electron gain enthalpy.
This contrast makes the difference in electron gain enthalpies largest between Neon (Ne) and Chlorine (Cl).
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Enthalpy change Questions
- Decreasing order of electron gain enthalpy of the following elements (magnitude only)
Sulphur A, Bromine - B, Fluorine C, Argon D 
If standard enthalpy of vaporization of \(CCl_4\) is \(30.5\) kJ/mol, find heat absorbed for vaporization of \(294 \) gm of \(CCl_4\). [Nearest integer] [in kJ/mol]
- $\text{Standard enthalpy of vaporisation for CCl}_4 \text{ is 30.5 kJ mol}^{-1}. \text{ Heat required for vaporisation of } 284 \, \text{g of CCl}_4 \text{ at constant temperature is } \_\_\_\_ \, \text{kJ.} \\ \text{(Given molar mass in g mol}^{-1}\text{; C = 12, Cl = 35.5)}$
- $\text{Two reactions are given below:}$ \[ 2\text{Fe}_{(s)} + \frac{3}{2}\text{O}_{2(g)} \rightarrow \text{Fe}_2\text{O}_{3(s)}, \Delta H^\circ = -822 \, \text{kJ/mol} \] \[ \text{C}_{(s)} + \frac{1}{2}\text{O}_{2(g)} \rightarrow \text{CO}_{(g)}, \Delta H^\circ = -110 \, \text{kJ/mol} \] $\text{Then enthalpy change for the following reaction}$ \[ 3\text{C}_{(s)} + \text{Fe}_2\text{O}_{3(s)} \rightarrow 2\text{Fe}_{(s)} + 3\text{CO}_{(g)} \]
Top JEE Main Questions
- In a hydrogen like atom, when an electron jumps from the $M$ - shell to the $L$ - shell, the wavelength of emitted radiation is $\lambda$. If an electron jumps from $N$-shell to the $L$-shell, the wavelength of emitted radiation will be :
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.