1. Calculate millimoles of NaOH:
\[ \text{Millimoles of NaOH} = 0.24 \times 25 = 6 \, \text{mmol}. \]
2. Since the acid is monobasic, millimoles of acid required = millimoles of NaOH = 6 mmol.
3. Mass of acid required:
\[ \text{Mass of acid} = 6 \times 24.2 = 145.2 \, \text{mg}. \]
4. Volume of acid solution:
Using \(\text{Volume} = \frac{\text{mass}}{\text{density}}\),
\[ V = \frac{145.2}{1.21 \times 10^3} = 0.12 \, \text{mL}. \]
5. Convert to \(10^{-3}\):
\[ V = 12 \times 10^{-3} \, \text{mL}. \]
Thus, the volume required is 12 \(\times\) \(10^{-3} mL\).
Neutralization of a monobasic acid requires equal millimoles of acid and base. Use the density of the acid solution to calculate the required volume.


MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]
An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :

Organic Chemistry is a subset of chemistry dealing with compounds of carbon. Therefore, we can say that Organic chemistry is the chemistry of carbon compounds and is 200-225 years old. Carbon forms bond with itself to form long chains of hydrocarbons, e.g.CH4, methane and CH3-CH3 ethane. Carbon has the ability to form carbon-carbon bonds quite elaborately. Polymers like polyethylene is a linear chain where hundreds of CH2 are linked together.
Read Also: Organic Compounds
Organic chemistry is applicable in a variety of areas including-