Question

The current population of a city is 11,02,500. If it has been increasing at the rate of 5% per annum, what was its population 2 years ago? 
 

• A. 9,92,500
• B. 9,95,006
• C. 10,00,000
• D. 12,51,506

Hint:

To find the population in the past, divide the current population by \( (1 + \text{rate})^n \), where \( n \) is the number of years.

Answer 1

The Correct Option is C

Let the population 2 years ago be \( P \). The population increases at a rate of 5% per annum, so after 2 years, the population becomes: \[ P \times (1 + 0.05)^2 = 11,02,500 \] Solving for \( P \): \[ P \times 1.1025 = 11,02,500 \] \[ P = \frac{11,02,500}{1.1025} = 10,00,000 \] Thus, the population 2 years ago was 10,00,000. The correct answer is option (C). 
Final Answer: (C) 10,00,000