Question:
The current population of a city is 11,02,500. If it has been increasing at the rate of 5% per annum, what was its population 2 years ago?
The current population of a city is 11,02,500. If it has been increasing at the rate of 5% per annum, what was its population 2 years ago?
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To find the population in the past, divide the current population by \( (1 + \text{rate})^n \), where \( n \) is the number of years.
Updated On: Jan 2, 2026
- 9,92,500
- 9,95,006
- 10,00,000
- 12,51,506
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The Correct Option is C
Solution and Explanation
Let the population 2 years ago be \( P \). The population increases at a rate of 5% per annum, so after 2 years, the population becomes: \[ P \times (1 + 0.05)^2 = 11,02,500 \] Solving for \( P \): \[ P \times 1.1025 = 11,02,500 \] \[ P = \frac{11,02,500}{1.1025} = 10,00,000 \] Thus, the population 2 years ago was 10,00,000. The correct answer is option (C).
Final Answer: (C) 10,00,000
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