Question:

The correct statement about the magnetic properties of \([\mathrm{Fe(CN)_6}]^{3-}\) and \([\mathrm{FeF_6}]^{3-}\) is : (Z = 26).

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Both complexes contain \(Fe^{3+}\) (d5); count unpaired electrons for strong field CN- and weak field F-.
Updated On: Nov 11, 2026
  • Both are paramagnetic.
  • Both are diamagnetic.
  • \([\mathrm{Fe(CN)_6}]^{3-}\) is paramagnetic, \([\mathrm{FeF_6}]^{3-}\) is diamagnetic.
  • \([\mathrm{Fe(CN)_6}]^{3-}\) is diamagnetic, \([\mathrm{FeF_6}]^{3-}\) is paramagnetic.
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The Correct Option is A

Solution and Explanation

Fe (Z = 26) = [Ar]3d6 4s2, so \(\mathrm{Fe^{3+}}\) = 3d5.
\(\mathrm{CN^-}\) is a strong-field ligand: electrons pair up as \(t_{2g}^5e_g^0\), 1 unpaired electron, paramagnetic (d2sp3).
\(\mathrm{F^-}\) is a weak-field ligand: \(t_{2g}^3e_g^2\), 5 unpaired electrons, paramagnetic (sp3d2).
Both are paramagnetic.
Answer: (1) Both are paramagnetic.
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