The correct stability order of the following diazonium salts is: 
Choose the correct answer from the options given below:
C $>$ A $>$ D $>$ B
Step 1: Basic stability rule for diazonium salts.
Aryl diazonium salts are stabilized by electron donating groups on the benzene ring and destabilized by strong electron withdrawing groups.
Step 2: Effect of substituents.
(A) $-OCH_3$: Strong $+M$ (electron donating) effect, stabilizes diazonium ion greatly.
(C) H: No substituent effect, moderate stability.
(D) $-CN$: Strong $-M$ effect, reduces stability.
(B) $-NO_2$: Very strong $-M$ and $-I$ effects, maximum destabilization.
Step 3: Ordering stability.
\[ \text{A (most stable)}>\text{C}>\text{D}>\text{B (least stable)} \] Step 4: Final conclusion.
The correct stability order is A $>$ C $>$ D $>$ B, corresponding to option (1).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)