The correct stability order of the following diazonium salts is: 
Choose the correct answer from the options given below:
C $>$ A $>$ D $>$ B
Step 1: Basic stability rule for diazonium salts.
Aryl diazonium salts are stabilized by electron donating groups on the benzene ring and destabilized by strong electron withdrawing groups.
Step 2: Effect of substituents.
(A) $-OCH_3$: Strong $+M$ (electron donating) effect, stabilizes diazonium ion greatly.
(C) H: No substituent effect, moderate stability.
(D) $-CN$: Strong $-M$ effect, reduces stability.
(B) $-NO_2$: Very strong $-M$ and $-I$ effects, maximum destabilization.
Step 3: Ordering stability.
\[ \text{A (most stable)}>\text{C}>\text{D}>\text{B (least stable)} \] Step 4: Final conclusion.
The correct stability order is A $>$ C $>$ D $>$ B, corresponding to option (1).
Arrange the following carbanions in the decreasing order of stability:
I. $p$-$\mathrm{Br{-}C_6H_4{-}CH_2^-}$
II. $\mathrm{C_6H_5{-}CH_2^-}$
III. $p$-$\mathrm{CH_3O{-}C_6H_4{-}CH_2^-}$
IV. $p$-$\mathrm{CHO{-}C_6H_4{-}CH_2^-}$
V. $p$-$\mathrm{CH_3{-}C_6H_4{-}CH_2^-}$
Choose the correct answer from the options given below:
If a random variable \( x \) has the probability distribution 
then \( P(3<x \leq 6) \) is equal to