Question

The correct order of N-compounds in its decreasing order of oxidation states is

• A. HNO₃, NO, N₂, NH₄Cl
• B. HNO₃, NH₄CI, NO, N₂
• C. HNO₃, NO, NH₄Cl, N₂
• D. NH₄Cl, N₂, NO, HNO₃

Answer 1

The Correct Option is A

To determine the correct order of N-compounds in decreasing order of oxidation states, we need to calculate the oxidation state of nitrogen in each compound provided:

1. HNO₃: The oxidation state of hydrogen is +1 and oxygen is -2. Let the oxidation state of nitrogen be x.
   The formula for calculating oxidation states is: +1 + x + 3(-2) = 0.
   Solving: x - 5 = 0
   Thus, x = +5.
2. NO: Oxygen has an oxidation state of -2. Let the oxidation state of nitrogen be x.
   The formula is: x - 2 = 0.
   Solving: x = +2.
3. N₂: In its elemental form, the oxidation state of nitrogen is 0.
4. NH₄Cl: Hydrogen is +1 and since there are four hydrogens, it contributes +4. Chlorine is -1.
   Let the oxidation state of nitrogen be x.
   The formula for calculating oxidation states is: x + 4(1) - 1 = 0.
   Solving: x + 3 = 0
   Thus, x = -3.

Using the calculations above, we can arrange the oxidation states in decreasing order: +5, +2, 0, -3. Therefore, the decreasing order of oxidation states for the compounds is:

HNO₃, NO, N₂, NH₄Cl.

Thus, the correct option is HNO₃, NO, N₂, NH₄Cl.