The correct order of hydration enthalpies is
(A) K+
(B) Rb2+
(C) Mg2+
(D) Cs+
(E) Ca2+
Choose the correct answer from the options given below:
For hydration enthalpy trends:
• Smaller ions with higher charges have greater hydration enthalpies.
• Compare ionic radii and charges to establish trends within groups and periods.
Hydration enthalpy depends on the charge density of ions, which is determined by the charge on the ion and its ionic radius.
Smaller ions with higher charges have higher hydration enthalpies due to stronger electrostatic interactions with water molecules.
For alkali metal ions:
\[\text{K}^+ > \text{Rb}^+ > \text{Cs}^+ \quad \text{(A > B > D)}.\]
This is because \(\text{K}^+\) is smaller than \(\text{Rb}^+\) and \(\text{Cs}^+\).
For alkaline earth metal ions:
\[\text{Mg}^{2+} > \text{Ca}^{2+} \quad \text{(C > E)}.\]
\(\text{Mg}^{2+}\) has a smaller radius and higher charge density than \(\text{Ca}^{2+}\).
Final Order:
\[\text{Mg}^{2+} > \text{Ca}^{2+} > \text{K}^+ > \text{Rb}^+ > \text{Cs}^+ \quad \text{(C > E > A > B > D)}.\]
Final Answer: \((4)\) \(\mathbf{C > E > A > B > D}\).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are

If standard enthalpy of vaporization of \(CCl_4\) is \(30.5\) kJ/mol, find heat absorbed for vaporization of \(294 \) gm of \(CCl_4\). [Nearest integer] [in kJ/mol]
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)