The stability of complexes is often related to the value of \( \Delta \), which is the energy difference between the d-orbitals in the ligand field. Higher \( \Delta \) values typically correspond to more stable complexes.
Based on the \( \Delta \) values:
- \( [{Fe(CN)}_6]^{3-} \) has the highest \( \Delta \) value due to the strong field ligand \( {CN}^- \), making it the most stable complex.
- \( [{Co(CN)}_6]^{3-} \) is slightly less stable compared to \( [{Fe(CN)}_6]^{3-} \).
- \( [{Mn(CN)}_6]^{3-} \) has the lowest \( \Delta \) value and is the least stable among these complexes. Thus, the correct increasing order of stability is \( {III}<{II}<{IV}<{I} \).
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are


What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)