Question:
The coordination number of $Sr^{2+}$ ion in $SrF_2$, if ionic radii are r $(Si^{2+})$ = 113 pm and r $(F^-)$ = 136 pm; is
The coordination number of $Sr^{2+}$ ion in $SrF_2$, if ionic radii are r $(Si^{2+})$ = 113 pm and r $(F^-)$ = 136 pm; is
Updated On: Jul 7, 2022
- 6
- 8
- 12
- 4
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The Correct Option is B
Solution and Explanation
Radius ratio $ = \frac{r^+}{r^-} = \frac{113}{136}$
$ = 0.830 > 0.732$.
The coordination number of $Sr^{2+}$ is $8$.
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Concepts Used:
Properties of Solids
Properties of Solids:
- In solids, particles are tightly or closely packed.
- Solids are incompressible, meaning the constituent particle is arranged close to each other and because of that, there is negligible space between the constituent particle.
- Solids are rigid, due to lack of space between the constituent particles which make it rigid or fixed.
- Solids have definite mass, volume and shape due to which it has a compact arrangement of constituent particles.
- The intermolecular distance between molecules is short.
- The rate of diffusion in solids is very low.
Read More: Solid State