To determine the coordination environment of the \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \), we need to understand how \( \text{EDTA}^{4-} \) acts as a ligand and coordinates with metal ions.
Step 1: Understanding EDTA as a ligand.
Step 2: Coordination Geometry of \( \text{Ca}^{2+} \) with EDTA.
Step 3: Conclusion and Verification.
Thus, the correct answer is that the coordination environment of \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \) is octahedral.
To determine the coordination environment of the \( \text{Ca}^{2+} \) ion in its complex with \( \text{EDTA}^{4-} \), we need to understand the structure and binding nature of \( \text{EDTA}^{4-} \).
\( \text{EDTA}^{4-} \) (ethylenediaminetetraacetic acid) is a hexadentate ligand, which means it can form six bonds with a metal ion. It does this by using its four carboxylate groups and two amine groups. This ability to form six coordinate bonds with a metal ion typically leads to an octahedral geometry.
Let's evaluate each option:
Based on the above analysis, the correct choice is \(octahedral\) because \( \text{EDTA}^{4-} \) provides six coordination sites equating to an octahedral coordination environment.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)