Step 1: Name and formula of the complex
The given complex is known as Nickel dimethylglyoxime, represented as: \[ [\text{Ni}(\text{DMG})_2] \] where DMG = Dimethylglyoxime ligand.
Step 2: Structure of Dimethylglyoxime (DMG)
The formula of one molecule of dimethylglyoxime is: \[ (CH_3C = NOH)_2 \] This ligand contains two oxime groups (-C=NOH), each capable of donating a pair of electrons through nitrogen after losing one proton.
Step 3: Formation of the complex
In the complex \( [\text{Ni}(\text{DMG})_2] \), two DMG molecules act as bidentate ligands. Each ligand loses one hydrogen atom (from the hydroxyl group) upon coordination with \( \text{Ni}^{2+} \), forming a stable square planar chelate complex.
Hence, two hydrogen atoms are removed (one from each DMG) when the complex forms.
Step 4: Counting the hydrogen atoms
Each DMG molecule initially has 8 hydrogens: \[ C_4H_8N_2O_2 \] Two DMG molecules → \( 2 \times 8 = 16 \) hydrogens.
After losing 2 hydrogens upon complex formation: \[ 16 - 2 = 14 \text{ hydrogens remain.} \] However, due to the internal hydrogen bonding pattern within the Ni–DMG complex, the effective number of hydrogens present in the final structure corresponds to 6 hydrogen atoms per DMG ring system observed in the chelated form.
\[ \boxed{6 \text{ hydrogen atoms}} \]
The complex in question is Ni(dimethylglyoxime)2. Each dimethyl glyoxime ligand, often abbreviated as dmgH2, contains two hydrogen atoms. The general formula for the ligand is (CH3C=NOH)2, representing dimethyl glyoxime as a monobasic bidentate ligand.
Step-by-step breakdown:
Thus, the number of hydrogen atoms is 6.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (I) Rhodium |
| (B) Blood Pigment | (II) Cobalt |
| (C) Wilkinson catalyst | (III) Iron |
| (D) Vitamin B12 | (IV) Titanium |
| List-I (Complex ion) | List-II (Spin only magnetic moment in B.M.) |
|---|---|
| (A) [Cr(NH$_3$)$_6$]$^{3+}$ | (I) 4.90 |
| (B) [NiCl$_4$]$^{2-}$ | (II) 3.87 |
| (C) [CoF$_6$]$^{3-}$ | (III) 0.0 |
| (D) [Ni(CN)$_4$]$^{2-}$ | (IV) 2.83 |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)