Step 1: Recall $Y_{\text{bus}$ properties.}
- Off-diagonal entry $Y_{ij}$ corresponds to $-Y_{line}(i,j)$.
- Diagonal entry $Y_{ii}$ is the sum of admittances connected to bus $i$, i.e.
\[
Y_{ii} = \sum_{j\neq i} Y_{line}(i,j) + Y_{\text{shunt},i}.
\]
Step 2: Check line admittances from off-diagonal terms.
From the matrix:
- Between bus 1 and bus 2: $Y_{12} = j10 \;\Rightarrow\; Y_{line}(1,2)= -j10$.
- Between bus 1 and bus 3: $Y_{13} = j5 \;\Rightarrow\; Y_{line}(1,3)=-j5$.
- Between bus 2 and bus 3: $Y_{23} = j4 \;\Rightarrow\; Y_{line}(2,3)=-j4$.
Thus, three lines exist: 1–2, 1–3, 2–3.
Step 3: Check diagonal entries.
- For bus 1:
\[
Y_{11} = -j15, \text{expected from lines } = -(j10+j5) = -j15.
\]
So no shunt element at bus 1.
- For bus 2:
\[
Y_{22} = -j13.5, \text{expected from lines } = -(j10+j4) = -j14.
\]
Difference: $0.5j$, indicating a shunt capacitor at bus 2.
- For bus 3:
\[
Y_{33} = -j8, \text{expected from lines } = -(j5+j4) = -j9.
\]
Difference: $j1$, indicating a shunt capacitor at bus 3.
Step 4: Interpret results.
- All three lines (1–2, 1–3, 2–3) have line charging capacitances.
- Shunt capacitances are present at bus 2 and bus 3.
Step 5: Evaluate options.
- (A) True: All three lines have finite capacitances.
- (B) False: Not only line 2–3, all lines exist. This can NOT be true.
- (C) False: Shunt capacitor is not at bus 1, but at buses 2 and 3.
- (D) False: Shunt capacitor is not only at bus 3, but also at bus 2.
% Final Answer
\[
\boxed{\text{Option (B)}}
\]
Given an open-loop transfer function \(GH = \frac{100}{s}(s+100)\) for a unity feedback system with a unit step input \(r(t)=u(t)\), determine the rise time \(t_r\).
Consider a linear time-invariant system represented by the state-space equation: \[ \dot{x} = \begin{bmatrix} a & b -a & 0 \end{bmatrix} x + \begin{bmatrix} 1 0 \end{bmatrix} u \] The closed-loop poles of the system are located at \(-2 \pm j3\). The value of the parameter \(b\) is: