For a balanced bridge, the relationship between the components is given by the following equation:
\[
\frac{R_1}{R_2} = \frac{L_3}{R_4 C_2}.
\]
Substitute the given values:
\[
\frac{100}{210} = \frac{L_3}{50 \times 2.9 \times 10^{-6}}.
\]
Solving for \( L_3 \):
\[
L_3 = \frac{100}{210} \times 50 \times 2.9 \times 10^{-6} = 14.4 \times 10^{-3} \, \text{H} = 14.40 \, \text{mH}.
\]
Thus, the value of \( L_3 \) is \( 14.40 \, \text{mH} \).