Question:

The bond angles in the following molecules decreases in the order \( BF_3, NH_3, PF_3 \) and \( XeF_2 \)

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More lone pairs decrease bond angleLinear molecules have maximum bond angle (180°).
Updated On: May 6, 2026
  • \( NH_3 > PF_3 > XeF_2 > BF_3 \)
  • \( XeF_2 > BF_3 > NH_3 > PF_3 \)
  • \( BF_3 > NH_3 > XeF_2 > PF_3 \)
  • \( PF_3 > BF_3 > NH_3 > XeF_2 \)
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The Correct Option is B

Solution and Explanation

Step 1: Identify molecular geometry.
\[ BF_3 \rightarrow \text{Trigonal planar (120°)} \]
\[ NH_3 \rightarrow \text{Trigonal pyramidal (~107°)} \]
\[ PF_3 \rightarrow \text{Trigonal pyramidal (less than 107°)} \]
\[ XeF_2 \rightarrow \text{Linear (180°)} \]

Step 2: Compare bond angles.

\[ XeF_2 = 180^\circ \]
\[ BF_3 = 120^\circ \]
\[ NH_3 \approx 107^\circ \]
\[ PF_3 < 107^\circ \]

Step 3: Arrange in decreasing order.

\[ 180^\circ > 120^\circ > 107^\circ > \text{(less than 107°)} \]
\[ XeF_2 > BF_3 > NH_3 > PF_3 \]

Step 4: Final conclusion.

\[ \boxed{XeF_2 > BF_3 > NH_3 > PF_3} \]
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