Question:
The base period is \(100\) days and the duty of the canal is \(1000\) hectares per cumec, then the depth of water will be
The base period is \(100\) days and the duty of the canal is \(1000\) hectares per cumec, then the depth of water will be
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Remember the irrigation formula:
\[
\boxed{
\Delta=\frac{8.64B}{D}
}
\]
where \(\Delta\) is obtained in metres.
Updated On: Jul 23, 2026
- \(0.864\) cm
- \(8.64\) cm
- \(86.4\) cm
- \(864\) cm
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The Correct Option is C
Solution and Explanation
Concept:
The relationship between duty (\(D\)), base period (\(B\)) and delta (\(\Delta\)) is
\[
\boxed{
\Delta=\frac{8.64B}{D}
}
\]
where
\[
\Delta=\text{Depth of water (m)},
\]
\[
B=\text{Base period (days)},
\]
\[
D=\text{Duty (hectares/cumec)}.
\]
Step 1: Write the given data. \[ B=100\text{ days} \] \[ D=1000\text{ hectares/cumec} \]
Step 2: Calculate the depth of water. Using \[ \Delta=\frac{8.64\times100}{1000} =0.864\text{ m} \] Converting into centimetres, \[ 0.864\times100=86.4\text{ cm} \] Hence, \[ \boxed{\Delta=86.4\text{ cm}} \] Therefore, the correct option is \[ \boxed{(C)\;86.4\text{ cm}.} \]
Step 1: Write the given data. \[ B=100\text{ days} \] \[ D=1000\text{ hectares/cumec} \]
Step 2: Calculate the depth of water. Using \[ \Delta=\frac{8.64\times100}{1000} =0.864\text{ m} \] Converting into centimetres, \[ 0.864\times100=86.4\text{ cm} \] Hence, \[ \boxed{\Delta=86.4\text{ cm}} \] Therefore, the correct option is \[ \boxed{(C)\;86.4\text{ cm}.} \]
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