The average molar mass of chlorine is 35.5 g mol\(^{-1}\). The ratio of \(^{35}\mathrm{Cl}\) to \(^{37}\mathrm{Cl}\) in naturally occuring chlorine is close to :
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- 1 : 1
- 2 : 1
- 3 : 1
- 4 : 1
The Correct Option is C
Solution and Explanation
Average mass \(= 35x + 37(1-x) = 37 - 2x = 35.5\).
\(2x = 1.5 \Rightarrow x = 0.75\); so \(^{35}\mathrm{Cl}\) : \(^{37}\mathrm{Cl}\) = 0.75 : 0.25 = 3 : 1.
Answer: (3) 3 : 1
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