Question:

The average age of 10 children is 14 years. If two children of ages 13 years and 10 years left this group and another two children having ages 7 years and 6 years joined, then the average age of this new group is x. If the two children who left from the original group rejoins this new group, then the average age of this group is less than x by:

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Average = $\frac{\text{Total Sum}}{\text{Number of observations}}$.
Updated On: Jun 26, 2026
  • 3/4
  • 1/4
  • 7/4
  • 15/14
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The Correct Option is B

Solution and Explanation

Step 1: Concept
Averages and sum of observations.

Step 2: Analysis

Initial sum = $10 \times 14 = 140$.
Sum after 2 left and 2 joined = $140 - (13 + 10) + (7 + 6) = 140 - 23 + 13 = 130$.
New average $x = \frac{130}{10} = 13$.

Step 3: Calculation

Sum when the original two rejoin = $130 + 23 = 153$.
Total children = $10 + 2 = 12$.
New average = $\frac{153}{12} = 12.75$.
Difference = $13 - 12.75 = 0.25 = 1/4$.

Step 4: Conclusion

Hence, the average is less than x by 1/4. Final Answer: (B)
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