The atomic radius in pm of Mg, P, Si, Al respectively is:
Show Hint
- \( 160, 143, 117, 110 \)
- \( 110, 117, 143, 160 \)
- \( 160, 110, 117, 143 \)
- \( 110, 160, 143, 117 \)
The Correct Option is C
Approach Solution - 1
Trend in Atomic Radii Across a Period
Atomic radii generally decrease as you move from left to right across a period in the periodic table. This is due to the increasing nuclear charge, which pulls the electrons closer to the nucleus.
Trend in Atomic Radii Down a Group
Atomic radii generally increase as you move down a group in the periodic table. This is because the number of electron shells increases, placing the outermost electrons farther from the nucleus.
Applying the Trend to Mg, P, Si, and Al
Mg (Magnesium): Group 2, Period 3
P (Phosphorus): Group 15, Period 3
Si (Silicon): Group 14, Period 3
Al (Aluminum): Group 13, Period 3
Since all four elements are in the same period (Period 3), we expect the atomic radius to decrease from left to right:
Mg > Al > Si > P
Therefore, the correct order of atomic radii is 160 pm (Mg), 110 pm (Al), 117 pm (Si), 143 pm (P).
Approach Solution -2
To solve this problem, we need to know the atomic radii of the elements magnesium (Mg), phosphorus (P), silicon (Si), and aluminum (Al).
1. Atomic Radii Trend:
The atomic radius generally decreases across a period from left to right and increases down a group. Based on this trend and the known atomic radii of these elements:
- Magnesium (Mg), an alkaline earth metal, has the largest atomic radius.
- Phosphorus (P), a non-metal, has a smaller atomic radius than magnesium but larger than silicon.
- Silicon (Si) comes next, with a smaller atomic radius compared to phosphorus.
- Aluminum (Al), being a metal, has the smallest atomic radius of these elements.
2. Analyzing the Options:
Option 1: 160, 143, 117, 110 (incorrect order).
Option 2: 110, 117, 143, 160 (incorrect order).
Option 3: 160, 110, 117, 143 (correct order).
This follows the atomic radius trend correctly, with magnesium having the largest atomic radius, followed by aluminum, silicon, and phosphorus
Option 4: 110, 160, 143, 117 (incorrect order).
3. Conclusion:
Based on the correct atomic radius order for these elements, the correct answer is Option C.
Final Answer:
The correct answer is Option C: 160, 110, 117, 143.
Top AP EAMCET Chemistry Questions
- If the $pK_a$ of acetic acid and $pK_b$ of dimethylamine are $4.76$ and $3.26$ respectively, the pH of dimethyl ammonium acetate solution is
- In the first order thermal decomposition of $C _{2} H _{5} I (g) \longrightarrow C _{2} H _{4}(g)+ HI (g)$, the reactant in the beginning exerts a pressure of $2$ bar in a closed vessel at $600 \,K$. If the partial pressure of the reactant is $0.1$ bar after $1000$ minutes at the same temperature the rate constant in $\min ^{-1}$ is $(\log 2=0.3010)$
- Isopropyl benzene on aerial oxidation followed by acid hydrolysis of the resulting compound yields
- Sodium nitrite is reacted with $H_2SO_4$ to form $NaHSO_4, HNO_3$, water and $X$. Gold is dissolved in aqua-regia to form water, $AuCl^{-}_4$ and $Y. X$ and $Y$ are respectively
- The average translational kinetic energy of a molecule in a gas becomes equal to $0.69\, eV$ at a temperature about [Boltzmann constant = $1.38 \times 10^{-23} \; J \; K^{-1}$]
Top AP EAMCET properties of d block elements Questions
- Identify the set of acidic oxides.
If uncertainty in position and momentum of an electron are equal, then uncertainty in its velocity is:
The graph shown below represents the variation of probability density, \( \Psi(r) \), with distance \( r \) of the electron from the nucleus. This represents:
Match the following elements with their correct classifications:
- What is the ratio of kinetic energies of \(3 \, {g}\) of hydrogen and \(4 \, {g}\) of oxygen at a certain temperature?
Top AP EAMCET Questions
- If $\int \cos x . \cos 2x . \cos 5x dx = A \; \sin 2x + B \sin 4x + C \sin 6x + D \sin 8x + k $ (where $k$ is the arbitrary constant of integration), then $\frac{1}{B} + \frac{1}{C} = $
- If $k$ is one of the roots of the equation $x^2 - 25x + 24 = 0 $ such that $A = \begin{bmatrix}1&2&1\\ 3&2&3\\ 1&1&k\end{bmatrix} $ is a non-singular matrix, then $A^{-1}$ =
- If only $\frac{1}{51}^{th}$ ot the main current is to be passed through a galvanometer then the shunt required is $R_1$ and if only $\frac{1}{11}^{th}$ of the main voltage is to be developed across the galvanometer, then the resistance required is $R_2$. Then $\frac{R_2}{R_1} =$
- If $p$ and $q$ are respectively the global maximum and global minimum of the function $f(x) = x^2 e^{2x}$ on the interval $[-2, 2]$ , then $pe^{-4} + qe^4 = $
- If $\displaystyle\sum^n_{k - 1} \tan^{-1} \left( \frac{1}{k^2 + k + 1} \right) = \tan^{-1} (\theta) $ , then $\theta$ =