Step 1: Understanding the Concept:
We are given the coordinates of the three vertices of a triangle and its area in terms of an unknown variable $P$. We need to compute the actual numerical area using a standard formula and equate it to the given expression to solve for $P$.
Step 2: Key Formula or Approach:
The area of a triangle defined by vertices $(x_1, y_1), (x_2, y_2)$, and $(x_3, y_3)$ can be calculated using the coordinate geometry formula:
$\text{Area} = \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$
Calculate this area, set the result equal to $\frac{P}{4}$, and solve the resulting algebraic equation.
Step 3: Detailed Explanation:
The given coordinates for the vertices are:
Vertex 1: $(x_1, y_1) = (3, 8)$
Vertex 2: $(x_2, y_2) = (-4, 2)$
Vertex 3: $(x_3, y_3) = (5, 1)$
Let's substitute these values into the area formula:
\[ \text{Area} = \frac{1}{2} |3(2 - 1) + (-4)(1 - 8) + 5(8 - 2)| \]
Compute the differences inside the parentheses:
\[ \text{Area} = \frac{1}{2} |3(1) - 4(-7) + 5(6)| \]
Perform the multiplications:
\[ \text{Area} = \frac{1}{2} |3 + 28 + 30| \]
Sum the values inside the absolute value bars:
\[ \text{Area} = \frac{1}{2} |61| \]
Since 61 is positive, the absolute value is just 61:
\[ \text{Area} = \frac{61}{2} \]
The problem states that the area is equivalent to the expression $\frac{P}{4}$. We can set up an equation:
\[ \frac{61}{2} = \frac{P}{4} \]
To isolate and solve for $P$, multiply both sides of the equation by 4:
\[ P = \frac{61}{2} \times 4 \]
\[ P = 61 \times \left(\frac{4}{2}\right) \]
\[ P = 61 \times 2 \]
\[ P = 122 \]
Step 4: Final Answer:
The value of $P$ is $122$.